Sex And The 06S6City
   
Monday, June 18, 2007
Ionic Equilibria
My fellow comrades fighting against the upcoming Block Test, the following is an interesting qns I found while revising for Ionic Equilibria. Quite challenging I thought, so I would like to share it with you guys.

pH of pure water at 25 degrees Celcius is 7.0
Kw = 1.0 X 10^-14 mol^2/dm^6 at 25 degrees Celcius

Calculate Ka for pure water at 25 degrees Celcius using the info given above. (In fact, I don't even need the value of Kw in my working... but there may be alternative ways... feel free to explore!)

If you need help to this qns, can ask me. Jia you!
posted by Terence (Hasegawa Masahiro) @ 7:38 pm  
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